Does anybody know, on an EA, how to get on a math operation

Dec 23, 2013 at 20:08
465 zobrazení
8 Replies
Členem od Jul 11, 2011   38 příspěvků
Dec 23, 2013 at 20:08
Does anybody know, on an EA, how to get on a math operation ( substraction to be specific) only positive numbers?
I am running into the problem that, for example, when the open price less than the close price, and the open price is smaller, the result is negative. I need this result to be positive, on other words, I need to substract ALWAYS the bigger price from the smaller price. Again, if someone knows how to do this, and is willing to share, that would be great.
Thank you
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forex_trader_136673
Členem od Jun 28, 2013   852 příspěvků
Dec 23, 2013 at 20:34
Multiply with -1

😄
pumpingmonkey
forex_trader_168526
Členem od Dec 19, 2013   126 příspěvků
Dec 23, 2013 at 21:10
double MathAbs( double value)
Returns the absolute value (modulus) of the specified numeric value.
Parameters:
value - Numeric value.

Sample:
  double dx=-3.141593, dy;
  // calc MathAbs
  dy=MathAbs(dx);
  Print('The absolute value of ',dx,' is ',dy);
  // Output: The absolute
 
pumpingmonkey
forex_trader_168526
Členem od Dec 19, 2013   126 příspěvků
Dec 23, 2013 at 21:37
ahuruglica posted:
Multiply with -1

😄

multiplying by negative one will only invert the negative or positive sign.

similar to doing a zero minus whatever your number is.

ie, if i have a variable X and i want to invert it...

x=0-x;

this will invert the sign, similar to multiplying by negative one.

the MathAbs function returns the absolute value of a signed number, whether it is positive or negative.

ie, xx=MathAbs(x);

happy coding.
Členem od Nov 21, 2011   1718 příspěvků
Dec 27, 2013 at 10:55
A= MathAbs(1.3800) = 1.3800
B= MathAbs(-1.3810) = 1.3810

So if A > B then A - B else B - A = 1.3810 - 1.3800 = 10 pips
Členem od Jul 11, 2011   38 příspěvků
Dec 27, 2013 at 23:31
Thanks to all for the answer. I do not think the multipling by -1 will do as this will only work if the result is negative, however, what is the result is positive? then, the multiplication's result would be negative
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Členem od Jul 11, 2011   38 příspěvků
Dec 27, 2013 at 23:31
Thank you, Crazytrader!
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forex_trader_136673
Členem od Jun 28, 2013   852 příspěvků
Dec 28, 2013 at 12:08 (Upravené Dec 28, 2013 at 12:09)
It was a little joke cause it remembered me primary school, and it was a math solution for many mathematical problems.

But it can work:

if A-B<0 then (A-B)*-1
if A-B>=0 then A-B


cheers
Členem od Jul 11, 2011   38 příspěvků
Dec 29, 2013 at 03:29
Thank you ahuruglica
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