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Does anybody know, on an EA, how to get on a math operation
Dec 23, 2013 at 20:08
Przeglądane 689
8 Replies
Dec 23, 2013 at 20:08
Does anybody know, on an EA, how to get on a math operation ( substraction to be specific) only positive numbers?
I am running into the problem that, for example, when the open price less than the close price, and the open price is smaller, the result is negative. I need this result to be positive, on other words, I need to substract ALWAYS the bigger price from the smaller price. Again, if someone knows how to do this, and is willing to share, that would be great.
Thank you
I am running into the problem that, for example, when the open price less than the close price, and the open price is smaller, the result is negative. I need this result to be positive, on other words, I need to substract ALWAYS the bigger price from the smaller price. Again, if someone knows how to do this, and is willing to share, that would be great.
Thank you
To win you have to risk loss
forex_trader_136673
Uczestnik z Jun 28, 2013
842 postów
Dec 23, 2013 at 20:34
Multiply with -1
😄
😄
forex_trader_168526
Uczestnik z Dec 19, 2013
126 postów
Dec 23, 2013 at 21:10
double MathAbs( double value)
Returns the absolute value (modulus) of the specified numeric value.
Parameters:
value - Numeric value.
Sample:
double dx=-3.141593, dy;
// calc MathAbs
dy=MathAbs(dx);
Print("The absolute value of ",dx," is ",dy);
// Output: The absolute
Returns the absolute value (modulus) of the specified numeric value.
Parameters:
value - Numeric value.
Sample:
double dx=-3.141593, dy;
// calc MathAbs
dy=MathAbs(dx);
Print("The absolute value of ",dx," is ",dy);
// Output: The absolute
forex_trader_168526
Uczestnik z Dec 19, 2013
126 postów
Dec 23, 2013 at 21:37
ahuruglica posted:
Multiply with -1
😄
multiplying by negative one will only invert the negative or positive sign.
similar to doing a zero minus whatever your number is.
ie, if i have a variable X and i want to invert it...
x=0-x;
this will invert the sign, similar to multiplying by negative one.
the MathAbs function returns the absolute value of a signed number, whether it is positive or negative.
ie, xx=MathAbs(x);
happy coding.
Uczestnik z Nov 21, 2011
1601 postów
Dec 27, 2013 at 10:55
A= MathAbs(1.3800) = 1.3800
B= MathAbs(-1.3810) = 1.3810
So if A > B then A - B else B - A = 1.3810 - 1.3800 = 10 pips
B= MathAbs(-1.3810) = 1.3810
So if A > B then A - B else B - A = 1.3810 - 1.3800 = 10 pips
Dec 27, 2013 at 23:31
Thanks to all for the answer. I do not think the multipling by -1 will do as this will only work if the result is negative, however, what is the result is positive? then, the multiplication's result would be negative
To win you have to risk loss
forex_trader_136673
Uczestnik z Jun 28, 2013
842 postów
Dec 28, 2013 at 12:08
(edytowane Dec 28, 2013 at 12:09)
It was a little joke cause it remembered me primary school, and it was a math solution for many mathematical problems.
But it can work:
if A-B<0 then (A-B)*-1
if A-B>=0 then A-B
cheers
But it can work:
if A-B<0 then (A-B)*-1
if A-B>=0 then A-B
cheers
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